The Physics of a Yo

The Physics of a Yo-yo

In everything that we do, there is some aspect of physics involved in it.
Even if we are just standing still on the ground, or leaning up against a wall,
there are still numerous forces acting upon us. This paper will tell of the
physics involved in throwing a yo-yo.

When you release a yo-yo, gravity acts on its center of mass to pull the
yo-yo downward. Because the string of the yo-yo is wrapped around the yo-yo\'s
axle, and because one end of the string is attached to your finger, the yo-yo is
forced to rotate as it drops. If the yo-yo could not rotate, it would not drop.

Just as any object falling in a gravitational field, the rate of drop
increases with time (it decreases 9.8 meters every second to be exact) and so,
necessarily, does the rotation rate of the yo-yo. The rate of drop and the
rotation rate are greatest when the bottom is reached and the string is
completely unwound. The spinning yo-yo contains rotational kinetic energy taken
from the gravitation potential energy through which the yo-yo has dropped.

Usually, the string is tied loosely around the axle so that the yo-yo can
continue to spin at the bottom. Because the full length of the string has been
laid out, the yo-yo can drop no further and, consequently, the rotation rate
cannot increase further. If left in this condition, the friction between the
axle and the string will eventually dissipate the energy

Wallin, 2

of rotation or, equivalently, the rotational kinetic energy of the yo-yo and
the yo-yo will come to rest.

However, a momentary tug on the string causes the friction between the string
and the axle briefly to increase so that the axle no longer slips within the
string. When the axle stops slipping, the rotational kinetic energy of the
spinning yo-yo is large enough to cause the string to wind around the axle. This
causes the yo-yo to begin to "climb" back up the string. After the
first one or two rotations, the string can no longer slip, so the process of
climbing up the string continues beyond the momentary application of the tug.

As the yo-yo continues to climb back up the string, the angular momentum
(rotational kinetic energy) of the yo-yo is converted back into gravitational
potential corresponding to the increasing height of the center of mass of the
yo-yo. For this reason, the yo-yo\'s rotational kinetic energy and, hence, its
rotation rate, steadily decreases as the yo-yo rises. This is, of course, the
reverse of the process when the yo-yo was dropped.

If not for frictional losses, the yo-yo would climb all the way back up the
string to your hand just as its rotational rate decreases to zero. But, due to
friction, the yo-yo does not quite make it all the way back up to your hand
before it stops rotating.

Thereafter, the process repeats, with the yo-yo returning short of its
previous height on each cycle. Eventually, the yo-yo comes to rest at the

Of course, as everyone knows, it is possible to keep the yo-yo going
indefinitely by giving it a slight upward pull on each cycle. This pull can be
combined with the tug required to initiate the climb back up the string. The
pull serves to give the center of mass of the yo-yo a little extra kinetic
energy to compensate for frictional losses, so that the

Wallin, 3

yo-yo can be kept going indefinitely.

Yo-yos can also be thrown horizontally, or launched in other directions. The
principle of operation is then just the same except that the kinetic energy of
the center of mass, which is converted into spin as the string unwinds, results
from being thrown, rather than from falling through a gravitational potential.

Category: Science