This essay *ENG 100 Lab 2 Report* has a total of 254 words and 4 pages.
ENG 100 Lab 2 Report

ENG 100, Lab 2

April 22, 2004

Thursday 1-4pm

Part A: series LC circuit:

Plot of amplitude (dB) versus frequency (Hz):

Plot of phase (degrees) versus frequency (Hz):

Calculation for pre-lab amplitude and phase results for 1600 Hz:

w = 2*p*1600 = 10053.1

Amplitude = 1/(1 + w2*L2/R2)1/2 = 1/(1 + (10053.1)2*(0.1)2/(1000)2)1/2 = 0.7052

dB = 20*log (Amplitude) = 20*log (0.7052) = -3.033

phase = -Atan(wL/R)*180/p = tan(10053.1*0.1/1000)*180/p = -45.152

Calculation for experimental amplitude and phase results for 1600 Hz:

Experimentally determined that VRMS = 0.694.

dB = 20log(VRMS) = 20*log(0.694) = -3.17

Experimentally determined that td (microsecond) = 70

Phase = -360*1600*td*10-6 = -40.32

Part B: Series RC Circuit, I:

Plot of amplitude (dB) versus frequency (Hz):

Plot of phase (degrees) versus frequency (Hz):

Results:

Configuration A is a low pass filter. (The amplitude (Vo/Vi) of the transfer function goes to 1 as omega goes to zero, and goes to zero as omega goes to infinity.) (The amplitude (dB) decreases as omega goes to infinity.)

Configuration B is a low pass filter. (The amplitude (Vo/Vi) of the transfer function goes to 1 as omega goes to zero, and goes to zero as omega goes to infinity.) (The amplitude (dB) decreases as omega goes to infinity.)

Conclusion:

The results (both amplitude (dB) and phase (degrees)) obtained in lab were similar to the prelab results for configurations A and B.

## Topics Related to ENG 100 Lab 2 Report

Linear filters, Signal processing, Amplitude, Equalization, Low-pass filter, Bode plot

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