From the graph, I am able to back up my theory. I can see when the enzyme is most active and when it starts to denature. From the graph, I have found out that, as the temperature increases, so does the catalyse activity, as it does not take as long to move the same distance, up to a certain point (59°C) where the activity’s slowly coming to a halt and levelling out. I found that the optimum for a catalyse is at 40°C. This is where the greatest number of collisions takes place between the enzyme and the substrate and therefore the highest rate of reaction is.

The rate was higher at the higher temperatures because as the temperature is raised, so is the energy level of the enzymes and substrate molecules. This means that they have more kinetic energy so they collide more often and therefore more reactions take place between them. This, in turn, means that the rate increases as more oxygen (O2) is produced. The enzyme denatured at about 49-50°C because the weak bonds, which hold the molecule into the specific shape for one substrate, are broken. The increase in molecular collisions and vibrations at higher temperatures is great enough to permanently change the shape of the active site. The enzyme is said to be denatured because it can no longer form an enzyme-substrate complex as its active site has been unalterably changed.
My prediction was correct in that there was very little activity in the cooler water baths (20°C) because the speed at which the enzymes and substrate molecules were moving was very slowly so there were not many collisions between them. The optimum temperature was 6-7°C away from what I predicted. (I originally predicted 42-43°C). So, overall the graph was gradually increasing on a gradient because as the temperature an increase so does the enzyme’s activity. It then reaches optimum temperature, (on my graph 51°C) before the gradient suddenly decreases as the enzyme is becoming de-natured.